Enjoy this latest quiz and let me know how you scored in the comments section here!
CCENT (100-101 ICND1) Sample Quiz 1
Enjoy this sample quiz where subnetting is the focus!
Congratulations - you have completed CCENT (100-101 ICND1) Sample Quiz 1.
You scored %%SCORE%% out of %%TOTAL%%.
Your performance has been rated as %%RATING%%
Your answers are highlighted below.
The decimal number 205 converted into a binary number is _____.
What is the decimal equivalent of the binary number 11000111?
Using six subnet bits, how many usable subnets are created?
What is the last usable host address on the third subnet for the following address and mask combination - 192.168.1.0 255.255.255.248?
Once you are finished, click the button below. Any items you have not completed will be marked incorrect.
There are 4 questions to complete.
Shaded items are complete.
You have completed
Your score is
You have not finished your quiz. If you leave this page, your progress will be lost.
Final Score on Quiz
Attempted Questions Correct
Attempted Questions Wrong
Questions Not Attempted
Total Questions on Quiz
Answer Choice(s) Selected
Need more practice!
Store and stream video tutorials, study materials and practice online tests at your convenience using a cloud hosted virtual PC by using CloudDesktopOnline.com. Visit Apps4Rent.com today to know how cloud technology can boost your productivity.
5 thoughts on “Subnetting Quiz”
I loved the questions scored 100% please post more this kind of questions are fun and boost our confidence to do the exam
OK – you got it. Just the other day I realized that I need to do more of these – thanks for confirming that!
the last question is a bit….weird.
Since subnet-zero was NOT mentioned. Why on earth would it be, 192.168.1.22?
The subnet-zero doesn’t exist.
Subnet-1) 192.168.1.0–>1st host=192.168.1.1 & last=192.168.1.6
Subnet-2) 192.168.1.8–>1st host=192.168.1.9 & last=192.168.1.14
*subnet-3) 192.168.1.16 is the network address so the first host is 192.168.0.17 and the last usable address is 192.168.1.22.
The question is referring to the *Third subnet
1st subnet 192.168.1.0 /29 = increment of 8
2nd subnet .8/29
3rd subnet .16/29
usable .17 – .22(Last Usable)
4th subnet .24/29